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Centre of gravity moment 1

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Acreeet

Mechanical
Aug 26, 2011
15
A perfectly balanced mass on beam A has it's centre of gravity shifted by the slight misalignment of beam A.

How do you calculate the bending moment on beam B generated by the CoG?

I'm not sure if there is any more information that needs providing to solve this problem but this is all I have currently.
 
 https://files.engineering.com/getfile.aspx?folder=1ff68fb7-aa58-4e4b-818d-55c8394ddad8&file=IMG20220620095058.jpg
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The image is a bit confusing. Does it need rotating?

Are those connections pins? If so why would any bending moment go into B?
 
Sketch orientation updated.

When cog is align with beam A, the mass is balanced and cannot topple. When cog is misaligned, the mass is more inclined to topple to the right (CW). Beam B acts as a support beam.
For e.g. if beam B is not strong enough, it may buckle under load generated by misalignment of cog.
 
If you disregard deflections in the system, Beam B would just get an axial force, not a bending moment. Solvable by statics.
 
Are we talking about beams or columns here?

What's your first attempt at a solution? If we assume the mass is rigid, it's a really simple solution to find with a free body diagram. If the mass isn't rigid, then it gets a bit more complex but not hard - from a design perspective it would be easy to box it in with an upper and lower bound solution.
 
"beam B would see a force that would buckle it." ... "would buckle it" or "could buckle it" ?

yes, in the RH sketch the weight is supported by both beams/columns ... loads by simple statics. no ??

another day in paradise, or is paradise one day closer ?
 
Assuming the connections are true pins (round), then this is solvable by statics and deflections in the beams don't matter. If there some kind of bearing plate between the beams that is going create a normal force at angle to the vertical, there could some second order lateral forces, but unless the box is very stiff and the beams are made of marshmallow, this will be negligible.
 
or is this box vibrating laterally, left-to-right ? which of course is a completely different situation.

another day in paradise, or is paradise one day closer ?
 
Some clarifications...
Beam A is infinitely rigid with the mass pin joined at the base to beam A.
Beam B is also infinitely rigid and pin jointed to the mass.

I'm interested in a simplified approach to estimate the normal force (-axis) or bending moment.

 
? if this is just statics ... the weight is supported by the two beams/columns ... like a simply supported beam. no??

another day in paradise, or is paradise one day closer ?
 
If it’s two pins then it is simple statics. If the centre of gravity is half way between, then 50% of the load goes to each beam, etc.
 
Post your attempt at a solution and I'm sure we can provide some confirmations, criticisms, and/or ideas. This is a pretty simple statics problem.
 
Are you suggesting beam A and beam B carry the load equally?

Now what if the distance from beam A to beam B is 10 m while the distance of cog from beam A remains as it is, 2m.

 
no, we are not (suggesting the two supports carry equal load). Go look up a simply supported beam in any text. it'll show how the load is proportioned between the two supports.
in your example A reacts 80% and B 20%.

if this is a simple static problem ...

another day in paradise, or is paradise one day closer ?
 
beam_cog_mpsbtq.jpg


PS : better if you study a bit more
 
Confusing presentation, how about telling us which way gravity is acting. No idea if a cantilevered beam or cantilevered column based on your responses. Is gravity acting from right to left parallel to the beams, or perpendicular to the beams?? How about some answers to the simple questions....

 
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