cdxx139
Mechanical
- Sep 19, 2009
- 393
Looking to do a heat loss through the steel hull of a dry dock. Half is under seawater. The water temp is 50 degF and the OA is 25 degF and indoor conditions being 60degF. SO I did a typical UAdT equation for both above water and underwater sections. U of steel being 1.2 and dT for above water being 35=(60-25) and dT for below water being 10=(60-50).
I was told my heat required in the hull is over sized from what they have in an older dry dock of comparable size. I was told I should be taking more of a credit for the portion above water, because of the portion below water.
So I went back to basics and opened my thermo book to Fourier's Law, but the k value has to do with the steel hull, not the fluid difference?
I am still looking but could use some assurance if its good enough or assistance if I am calculating incorrectly.
knowledge is power
I was told my heat required in the hull is over sized from what they have in an older dry dock of comparable size. I was told I should be taking more of a credit for the portion above water, because of the portion below water.
So I went back to basics and opened my thermo book to Fourier's Law, but the k value has to do with the steel hull, not the fluid difference?
I am still looking but could use some assurance if its good enough or assistance if I am calculating incorrectly.
knowledge is power