mech4321
Mechanical
- Jun 8, 2009
- 14
Hi,
We have to evaluate the power consumption of a fluid cooler which have at 600V an FLA of 23A. That would give approximately kw = 600 x 23 x 1.73 = 23.9 kw or 32 hp. However, the fluid cooler has only a total of motor of 6 x 1.5 hp = 9 hp (plus a small amount for the controls). Where does come this big differance? How can we evaluate the consumption at full load if this value is not available from the manufacturer.
Thanks
Alex
We have to evaluate the power consumption of a fluid cooler which have at 600V an FLA of 23A. That would give approximately kw = 600 x 23 x 1.73 = 23.9 kw or 32 hp. However, the fluid cooler has only a total of motor of 6 x 1.5 hp = 9 hp (plus a small amount for the controls). Where does come this big differance? How can we evaluate the consumption at full load if this value is not available from the manufacturer.
Thanks
Alex