Meck91
Mechanical
- Aug 26, 2009
- 33
Folks,
I tried to calculate pipe wall thickness as per ASME B31.1 Para. 304.1.2 & the “Pressure design thickness (t)” comes as 0.38106” for 24” SA-106 Gr. B pipe. Design pressure & temperature is 550 Psig & 600 Degree F respectively. Now,
1) When I added corrosion allowance of 1/16” in to the pressure design thickness (t), the value comes as [0.8106” + 1/16” = 0.44356”]
And later I added 12.5% wall thickness tolerance to 0.44356”, the adjusted thickness comes as 0.5069”. For 24” pipe the next greater commercial wall thickness available is 0.562” that corresponds to 24” schedule 30 pipe.
Now,
2) If I reverse the process and add 12.5% wall thickness first into the pressure design thickness (t), and later add corrosion allowance the final pipe thickness comes as 0.49799”, which means that I can use 24” XS pipe having a wall thickness of 0.500”.
Which method should I use (1) & (2). I know that the code formulas are for worst case scenario or in corroded condition, in that case I have to add corrosion allowance at the very first step and later to add mill tolerance. Some on-line calculation available also used method (1), however, some colleagues think to use method (2).
Would appreciate your feedback and/or comments.
Regards,
Meck91
I tried to calculate pipe wall thickness as per ASME B31.1 Para. 304.1.2 & the “Pressure design thickness (t)” comes as 0.38106” for 24” SA-106 Gr. B pipe. Design pressure & temperature is 550 Psig & 600 Degree F respectively. Now,
1) When I added corrosion allowance of 1/16” in to the pressure design thickness (t), the value comes as [0.8106” + 1/16” = 0.44356”]
And later I added 12.5% wall thickness tolerance to 0.44356”, the adjusted thickness comes as 0.5069”. For 24” pipe the next greater commercial wall thickness available is 0.562” that corresponds to 24” schedule 30 pipe.
Now,
2) If I reverse the process and add 12.5% wall thickness first into the pressure design thickness (t), and later add corrosion allowance the final pipe thickness comes as 0.49799”, which means that I can use 24” XS pipe having a wall thickness of 0.500”.
Which method should I use (1) & (2). I know that the code formulas are for worst case scenario or in corroded condition, in that case I have to add corrosion allowance at the very first step and later to add mill tolerance. Some on-line calculation available also used method (1), however, some colleagues think to use method (2).
Would appreciate your feedback and/or comments.
Regards,
Meck91