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DEEP DRAWING OF A CYLINDRICAL CUP

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skipps

Materials
Apr 19, 2020
11

hI was wondering if you can offer some help on this question how you calculated your values
THANK YOU

The blank is made of aluminum-killed steel, which is assumed to satisfy the Ramberg-Osgood relation between true stress and logarithmic strain,
ε=(σ/K)^(1/n)
with a reference stress value (K) of 513 MPa and a work-hardening exponent (n) of 0.223. Isotropic elasticity is assumed, with a Young's modulus of 211 GPa and a Poisson's ratio of 0.3. An initial yield stress of 91.3 MPa is obtained from these data. The stress-strain behavior is defined by piecewise linear segments matching the Ramberg-Osgood curve up to a total (logarithmic) strain level of 107%, with Mises yield, isotropic hardening, and no rate dependence."
 
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I’m not sure what you mean. Do you want to define this material in Abaqus ? There is a deformation plasticity model in this software that uses Ramberg-Osgood relationship. To define it you have to specify:
- Young’s modulus
- Poisson’s ratio
- yield stress σ_0
- exponent n
- yield offset α

α=K(σ_0/E)^(n-1)
 
for the excel on calculating strain values. the modelling part is ok i manage to finish it, its material excel values that i dont really know how to calcalate.
thank you
 
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