bjb
Structural
- Nov 8, 2002
- 455
In the 2001 NDS, equation 3.3-5, if you have a multi-ply beam, is the value of "b" to be used only the width of an individual ply or the total width of the built-up beam?
It seems to me that if the plies are well connected that "b" should be the width of the builtup beam. On the other hand, when it comes to the column stability factor, you can use the total width of the builtup column, but then have to reduce the Cp factor by 0.6 or 0.75 depending on if you nail or bolt the plies together. I see nothing in the NDS that addresses builtup beams.
I think that with a beam, normally the bending moment is not constant, so the compression force in the unsupported compression edge is not constant, and therefore some portions of the beam have less tendency to buckle than other more highly stressed areas. In a typical wood column the compressive force is usually constant between points of lateral support. Maybe this is a way to rationalize using the full width of a builtup wood beam without a reduction factor.
It seems to me that if the plies are well connected that "b" should be the width of the builtup beam. On the other hand, when it comes to the column stability factor, you can use the total width of the builtup column, but then have to reduce the Cp factor by 0.6 or 0.75 depending on if you nail or bolt the plies together. I see nothing in the NDS that addresses builtup beams.
I think that with a beam, normally the bending moment is not constant, so the compression force in the unsupported compression edge is not constant, and therefore some portions of the beam have less tendency to buckle than other more highly stressed areas. In a typical wood column the compressive force is usually constant between points of lateral support. Maybe this is a way to rationalize using the full width of a builtup wood beam without a reduction factor.