Sweguy
Mechanical
- Mar 12, 2009
- 13
Hi
I have a question regarding how the drive train in ball valves is allowed to be designed.
I don`t have the standard in front of me right now but I will try to remember.
The design torque is 2x the calculated torque for the valve.
When the design torque is applied on the valve the stresses in the drivetrain is not allowed to be higher then 67% of yield strenght.
I`m currently looking on some valves that shall be designed according to 6D, they has stem dimensions that I thinks is in line with the standard, but the connection between stem and ball seems to be very week, the surface loads between stem and ball must be much higher then 67% of yield strenght.
Can somebody explain this for me, is not surface loads calculated or is there other load limits?
I have a question regarding how the drive train in ball valves is allowed to be designed.
I don`t have the standard in front of me right now but I will try to remember.
The design torque is 2x the calculated torque for the valve.
When the design torque is applied on the valve the stresses in the drivetrain is not allowed to be higher then 67% of yield strenght.
I`m currently looking on some valves that shall be designed according to 6D, they has stem dimensions that I thinks is in line with the standard, but the connection between stem and ball seems to be very week, the surface loads between stem and ball must be much higher then 67% of yield strenght.
Can somebody explain this for me, is not surface loads calculated or is there other load limits?