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Driving current.

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samreen

Electrical
Aug 27, 2007
10
PK
if i have a coli of 242kW on a 110V Dc system...how much current is require to energize the coil?...i think a current of 2.2A would energize the cirucit....

 
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If you're asking how much current you need for 242kW at 110V DC then the answer is 2200A. If you're asking something different then I'm not sure what you're asking.


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If we learn from our mistakes I'm getting a great education!
 
I get the same answer as Scotty, 2200 Amps.

Bill
--------------------
"Why not the best?"
Jimmy Carter
 
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Keith Cress
kcress -
 
Maybe he is getting confused with AC single phase/polyphase and DC systems.

When it is DC then there is no Root 2 or root 3 factors, no instantaneous, or avg power to worry about.

Assuming it is a continuous load at steady state, then the Wattage is nice and easy at
W = V*I.
 
If kW should be W, then his result is correct. We're just being jerks!

Bill
--------------------
"Why not the best?"
Jimmy Carter
 
Or if 'A' should be 'kA'?


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I concede.
My assessment of the technical possibilities of this application was incomplete.

Bill
--------------------
"Why not the best?"
Jimmy Carter
 
I have done a rather thorough research on the subject and I did come up with an alternate answer that I believe can be of some interest. If we assume that m means "milli", M means "mega" and A means "ampere", then the following expression also holds:

I [mA] = P [kW] / U [MV]

Please note that this is a preliminary result. It may need to be checked in a model circuit.

Gunnar Englund
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100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...
 
We are all naughty. We must behave ourselves in public!


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