ChrisGreaves
Student
- Nov 11, 2024
- 1
New here. Aeronautics because I am curious about the cost of airflow around an object.
In my case a Toyota Rav4 driving down the highway; calm weather, dry etc. Just the Rav 4.
I first proposed this discussion on Eileen's Lounge, but a user suggested I check out at this site.
The Rav4 is five feet wide and five feet high in cross-section. Assume that there is no space between the road and the underside of the SUV. It moves down the road like a block of wood, 25 square feet in cross-section, pushing air out of the way.
If I assume that it pushes air five feet vertically, I calculate 4,500 foot pounds per second of work; that is lifting 60 square inches of air vertically by five feet, assuming 15 psi. At 60mph=88 fps= about 1,000 inches/second, this has left me contemplating that the car engine must be doing 4,500,000 foot-pounds of work each second.
But one horsepower is defined as 550 ft/lbs/second, which suggests that the car in my simple model is an 8,182 HP Toyota Rav4.
The Toyota RAV4 is 203 HP.
Please and Thank you, where is my error in thinking?
I can see that air might be pushed to the side rather than vertically, but then that air must do work to push other air to the side.. For me the bottom line is that where there was air occupying a 5'x5' cross section, there is now no air in the cross section - just steel, plastic, rubber etc.
I am trying to determine how much work is done just to make a car occupy air-space on a 3.5 hour trip along the highway.
Thanks for any advice on the calculation, also any tips about a more appropriate forum.
Cheers, Chris
In my case a Toyota Rav4 driving down the highway; calm weather, dry etc. Just the Rav 4.
I first proposed this discussion on Eileen's Lounge, but a user suggested I check out at this site.
The Rav4 is five feet wide and five feet high in cross-section. Assume that there is no space between the road and the underside of the SUV. It moves down the road like a block of wood, 25 square feet in cross-section, pushing air out of the way.
If I assume that it pushes air five feet vertically, I calculate 4,500 foot pounds per second of work; that is lifting 60 square inches of air vertically by five feet, assuming 15 psi. At 60mph=88 fps= about 1,000 inches/second, this has left me contemplating that the car engine must be doing 4,500,000 foot-pounds of work each second.
But one horsepower is defined as 550 ft/lbs/second, which suggests that the car in my simple model is an 8,182 HP Toyota Rav4.
The Toyota RAV4 is 203 HP.
Please and Thank you, where is my error in thinking?
I can see that air might be pushed to the side rather than vertically, but then that air must do work to push other air to the side.. For me the bottom line is that where there was air occupying a 5'x5' cross section, there is now no air in the cross section - just steel, plastic, rubber etc.
I am trying to determine how much work is done just to make a car occupy air-space on a 3.5 hour trip along the highway.
Thanks for any advice on the calculation, also any tips about a more appropriate forum.
Cheers, Chris