oliebol
Mechanical
- Jun 15, 2004
- 38
Hey all,
I have some automation problems in IV 10.
In a sketch, I have an arc which I would like to dimension by its arclength, since this variable is my inputvalue.
However, Inventor doesn't seem to have arclength dimensions available in the sketch environment.
So I tried to solve my problem by using an equation which converts an arclength to it's corresponding arcsegment-angle. (in combination with the arcradius)
The mathematical expression for an arcsegment is:
arclength= PI/180*radius*angle, which is the same as:
Angle = (arclength *180 )/(3,141592 *radius )
What goes wrong in IV is that the angle variable is set to [deg] and it's formula has different units like [mm].
How can I make this equation work?
Thanks for your help.
Greetz,
Martin
Unigraphics NX4,NX3,NX2,R17
Inventor 10,9,8,7
Solid Edge 10,9,8
Solid Works 2000,98
Mechanical Desktop 4,3
Autocad 2004DX,2000,R14, R12
Teamcenter 9
I have some automation problems in IV 10.
In a sketch, I have an arc which I would like to dimension by its arclength, since this variable is my inputvalue.
However, Inventor doesn't seem to have arclength dimensions available in the sketch environment.
So I tried to solve my problem by using an equation which converts an arclength to it's corresponding arcsegment-angle. (in combination with the arcradius)
The mathematical expression for an arcsegment is:
arclength= PI/180*radius*angle, which is the same as:
Angle = (arclength *180 )/(3,141592 *radius )
What goes wrong in IV is that the angle variable is set to [deg] and it's formula has different units like [mm].
How can I make this equation work?
Thanks for your help.
Greetz,
Martin
Unigraphics NX4,NX3,NX2,R17
Inventor 10,9,8,7
Solid Edge 10,9,8
Solid Works 2000,98
Mechanical Desktop 4,3
Autocad 2004DX,2000,R14, R12
Teamcenter 9