sshep
Chemical
- Feb 3, 2003
- 761
We are installing some specially designed cone strainers at the outlet of a reactor to catch any catalyst pellets which might break through. This is vapor service (H2 and vaporized hydrocarbons) at 900F and 40psig. I would like to estimate in advance the pressure drop of the proposed design (designed by others).
The strainer is the surface of a circular cone fustum built into a spool of 24"dia pipe (ID=23.25"). The cone shaped support plate is lined with wire mesh..
This is my geometry:
R1=19.25" (note: there is a 1/2" thick solid support ring holding the cone away from wall so the effective pipe cross-section at this point is 19.25" dia)
R2=5" (note: this is a flat steel plate at small end of cone)
H=47.75" (distance between base and top faces of cone)
Support plate open area=40% (as 1/8" perforations)
mesh wire size=0.025" (layed inside, flow is inside to out)
wires/inch=16 (note: this gives 40% open area in mesh)
I get the surface area of the cone part from the formula:
A = pi*(R1+R2)*(H^2+(R1-R2)^2))^.5 = 26.4sqft
with a clean open area of
26.4*0.4*0.4 = 4.2 sqft (vs 2.9 sqft cross-section area of pipe)
which all looks reasonable.
Now I am wondering if anyone can tell me how to relate the pressure drop of this spool in terms of equivalent length of 24" pipe? A bonus would be a method which can also estimate the pressure drop as the open area is reduced by plugage.
Any help is appreciated.
best wishes,
sshep
The strainer is the surface of a circular cone fustum built into a spool of 24"dia pipe (ID=23.25"). The cone shaped support plate is lined with wire mesh..
This is my geometry:
R1=19.25" (note: there is a 1/2" thick solid support ring holding the cone away from wall so the effective pipe cross-section at this point is 19.25" dia)
R2=5" (note: this is a flat steel plate at small end of cone)
H=47.75" (distance between base and top faces of cone)
Support plate open area=40% (as 1/8" perforations)
mesh wire size=0.025" (layed inside, flow is inside to out)
wires/inch=16 (note: this gives 40% open area in mesh)
I get the surface area of the cone part from the formula:
A = pi*(R1+R2)*(H^2+(R1-R2)^2))^.5 = 26.4sqft
with a clean open area of
26.4*0.4*0.4 = 4.2 sqft (vs 2.9 sqft cross-section area of pipe)
which all looks reasonable.
Now I am wondering if anyone can tell me how to relate the pressure drop of this spool in terms of equivalent length of 24" pipe? A bonus would be a method which can also estimate the pressure drop as the open area is reduced by plugage.
Any help is appreciated.
best wishes,
sshep