hadams417
Mechanical
- May 10, 2005
- 9
Please advise me on how to properly size a flash vessel. Here is my application:
Condensate inlet flowrate = 51, 348 lb/hr
Inlet pressure = 600 psig
Internal tank pressure = 160 psig
Which corresponds to 15.1% flash steam. Given this amount of flash steam for the given condensate flow, this corresponds to:
Steam Flow (from tank) = 51348 * .151 = 7753.6 lb/hr
Liquie Flow (from tank) = 51348 * (1-.151) = 43595 lb/hr
Now, using the specific volume data of the vapor and liquid (2.6 ft^3/lb and 53.6 ft^3/lb, respectively) and target velocities of 10 fps for the steam and 50 fps for the water exiting the tank, my calculations for the tank diamter are as follows:
Steam: Dia = [((7753.6*2.6)*4) / (3.14 * 36000)]^(1/2) = .844 ft = 10.1 in (dia. necessary to provide steam flow of 10fps)
Water: Dia = [((43595*53.6)*4) / (3.14 * 180000)]^1/2 = 4.07 ft = 49 in (dia. necessary to provide water flow of 50 fps)
Clearly these are substancially different diameters. I do not want to undersize my vessel and experience overflow as a result. However, I do not want to over size either. I am stuck at this point. How do I determine proper tank heigt? Ive read places that state "use a 3:4 ratio for dia. to height" and others that say "tank height = 3*dia or minimum of 36in). Please advise me on how to complete the sizing procedure.
Condensate inlet flowrate = 51, 348 lb/hr
Inlet pressure = 600 psig
Internal tank pressure = 160 psig
Which corresponds to 15.1% flash steam. Given this amount of flash steam for the given condensate flow, this corresponds to:
Steam Flow (from tank) = 51348 * .151 = 7753.6 lb/hr
Liquie Flow (from tank) = 51348 * (1-.151) = 43595 lb/hr
Now, using the specific volume data of the vapor and liquid (2.6 ft^3/lb and 53.6 ft^3/lb, respectively) and target velocities of 10 fps for the steam and 50 fps for the water exiting the tank, my calculations for the tank diamter are as follows:
Steam: Dia = [((7753.6*2.6)*4) / (3.14 * 36000)]^(1/2) = .844 ft = 10.1 in (dia. necessary to provide steam flow of 10fps)
Water: Dia = [((43595*53.6)*4) / (3.14 * 180000)]^1/2 = 4.07 ft = 49 in (dia. necessary to provide water flow of 50 fps)
Clearly these are substancially different diameters. I do not want to undersize my vessel and experience overflow as a result. However, I do not want to over size either. I am stuck at this point. How do I determine proper tank heigt? Ive read places that state "use a 3:4 ratio for dia. to height" and others that say "tank height = 3*dia or minimum of 36in). Please advise me on how to complete the sizing procedure.