meamin
Structural
- Aug 29, 2019
- 8
I've looked at other threads and I am still not sure I am understanding what all needs to happen with the slab to OK a building for the buoyance force from flood loads. I'll create a fictitious scenario here.
100 ft total square area (10' x 10' sides)
3 ft flood protection grade
Buoyance Force = 62.4pcf * 100 ft^2 * 3 ft fpg
Buoyancy Force = 18,720 lbs TOTAL
Now, I'll have a 100ft^2 wood roof, 10'+10'+10'+10' = 40' linear feet of 10' tall, 8" solid grouted wall, 40 linear feet of a 12" thick, 12" wide strip ftg.
Roof DL = 12psf * 100ft^2 = 1,200 lbs
Wall DL = 84psf * 40ft * 10ft = 33,600 lbs
Strip Ftg. DL = 150pcf * 1ft * 1ft * 40ft = 6,000 lbs
Building Weight (Slab not considered yet) = 40,800 lbs. > 18,720 lbs. buoyance force
Therefore, my building weight is greater than the buoyance force..Great news.
Now I just have to design my slab to span 10 ft for (62.4pcf*3ft) 187.2 psf minus the self wt. of the slab correct?
I should be able to reinforce an 8" thick slab for 187.2psf buoyance minus 100psf self wt. = 87.2psf
As long as I reinforce my slab to resist the shears and moments from an 87.2psf uplift load I am OK right?
It seems that the other idea is sizing the slab so that the DL overcomes the buoyance which would mean a 15" slab is required (187.5psf self wt.). I think this is incorrect since the net buoyancy is already overcome when you consider the footing, grouted walls, and roof load. Add in the 8" slab I am proposing and that is another 10,000 lbs of weight to overcome the 18,720 lbs. of buoyance.
Thoughts?
Thanks,
AM
100 ft total square area (10' x 10' sides)
3 ft flood protection grade
Buoyance Force = 62.4pcf * 100 ft^2 * 3 ft fpg
Buoyancy Force = 18,720 lbs TOTAL
Now, I'll have a 100ft^2 wood roof, 10'+10'+10'+10' = 40' linear feet of 10' tall, 8" solid grouted wall, 40 linear feet of a 12" thick, 12" wide strip ftg.
Roof DL = 12psf * 100ft^2 = 1,200 lbs
Wall DL = 84psf * 40ft * 10ft = 33,600 lbs
Strip Ftg. DL = 150pcf * 1ft * 1ft * 40ft = 6,000 lbs
Building Weight (Slab not considered yet) = 40,800 lbs. > 18,720 lbs. buoyance force
Therefore, my building weight is greater than the buoyance force..Great news.
Now I just have to design my slab to span 10 ft for (62.4pcf*3ft) 187.2 psf minus the self wt. of the slab correct?
I should be able to reinforce an 8" thick slab for 187.2psf buoyance minus 100psf self wt. = 87.2psf
As long as I reinforce my slab to resist the shears and moments from an 87.2psf uplift load I am OK right?
It seems that the other idea is sizing the slab so that the DL overcomes the buoyance which would mean a 15" slab is required (187.5psf self wt.). I think this is incorrect since the net buoyancy is already overcome when you consider the footing, grouted walls, and roof load. Add in the 8" slab I am proposing and that is another 10,000 lbs of weight to overcome the 18,720 lbs. of buoyance.
Thoughts?
Thanks,
AM