Equations for hydraulic jump in horizontal rectangular channel (Chaudhry, 1993; Chow, 1959):
V=Q/(yB) F=V/(gy)0.5 y2/y1 = 0.5 [(1+8F12 )0.5 - 1]
L = 220 y1 tanh[(F1-1)/22] h = (y2-y1)3 /(4y1y2)
where:
B=Channel width (m), F=Froude number (dimension-less), g=acceleration due to gravity (9.8066 m/s2), h=Head loss (m), L=Length of jump (m), Q=Discharge (m3/s), tanh=Hyperbolic tangent trigonometric function, V=Velocity (m/s), y=Water depth (m)