somacast
Mechanical
- Aug 10, 2010
- 88
Hello everybody,
At first kindly refer to this topic for earlier discussions as I was seeking help to calculate the heat transfer from the tank of a cooling system we want to enhance
Further to this (kindly refer to attachment), looking at the full system overhere, it appears that a big amount of BTU is required to cool this knowing that the pumps are 27 m3/hr each, so the first intention to follow our old practice of cooling the water tank with an AC unit evaporator as shown in previous thread wont do, I did calculate based on q(dot)= m(dot) * Cp * delta T , and the flow of water is known and assumed that we want to bring water temp from 55 C to 25 C ....
my questions are :
1- as far as I know that pumps in parallel means we add their flow rates, which means in our case here it would be 3 x 27= 81m3/h ... however by going to site and looking through the small observation opening at the top of the tank (1.5 m3) I would say that there is no way its 81 m3/hr .. because that would have meant that this tank would have emptied in a minute which does not happen... can you please tell me if Iam write ? is it 27 x 3 ? or the 27 is divided equally between the 3 pumps over here as they take from the same branch?
2- well q (dot) = m (dot) * Cp * delta T , in addition to heat losses from tank calculated earlier cover my BTU needs to cool ? assuming that the cooling happens in the tank or just after it by means of a chiller?
if required the following are the parameters of the system ... Pumps discharge pressure = 3.0 Kg/cm2 , tank pressure = Atm . pipes sizes are shown in the attached P&ID
At first kindly refer to this topic for earlier discussions as I was seeking help to calculate the heat transfer from the tank of a cooling system we want to enhance
Further to this (kindly refer to attachment), looking at the full system overhere, it appears that a big amount of BTU is required to cool this knowing that the pumps are 27 m3/hr each, so the first intention to follow our old practice of cooling the water tank with an AC unit evaporator as shown in previous thread wont do, I did calculate based on q(dot)= m(dot) * Cp * delta T , and the flow of water is known and assumed that we want to bring water temp from 55 C to 25 C ....
my questions are :
1- as far as I know that pumps in parallel means we add their flow rates, which means in our case here it would be 3 x 27= 81m3/h ... however by going to site and looking through the small observation opening at the top of the tank (1.5 m3) I would say that there is no way its 81 m3/hr .. because that would have meant that this tank would have emptied in a minute which does not happen... can you please tell me if Iam write ? is it 27 x 3 ? or the 27 is divided equally between the 3 pumps over here as they take from the same branch?
2- well q (dot) = m (dot) * Cp * delta T , in addition to heat losses from tank calculated earlier cover my BTU needs to cool ? assuming that the cooling happens in the tank or just after it by means of a chiller?
if required the following are the parameters of the system ... Pumps discharge pressure = 3.0 Kg/cm2 , tank pressure = Atm . pipes sizes are shown in the attached P&ID