Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations waross on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Forming Limit Diagrams in ABAQUS

Status
Not open for further replies.

EngPicci82

Mechanical
Sep 4, 2013
1
Hi there,

I'm a new user and I've decided to subscribe here because I need a help; I'm a mechanical engineer and I'm working on sheet metal forming, in particular hydroforming of aluminium sheet.
I'm actually building up the numerical model in ABAQUS (v.6.10), and I want to insert within the simulation the forming limit diagrams of the aluminium; the strains composing the FLDs come from experimental test performed in a laboratory, so all those values are right.
The initial model didn't have the FLDs implemented within the property module; in order to determine the fracture, I used to export the major and minor strain, to combine one with the other obtaining a strain path for a single node and then I compared the FLD with the strain path superimposed on the same graph; if the strain path intersects the FLD, the fracture occurs, otherwise no fracture happens.
In order to obtain a more global model, I tried to implement the FLD within the model itself; I followed the "trial-and-error" phylosophy and, at the end, I've modified my model in this way:
1- Property module -> I've inserted the option "Damage for Ductile Metals" and in particular "FLD Damage"
2- Step Module -> New Field Output, Failure/Fracture DMICRT (only applied on the sheet)
-> New History Output, Failure/Fracture - DMICRT - FLDCRT (only applied on the sheet)
In this way, on the Visualization Module I can plot the FLDCRT so I can understand if and where fracture occurs.
The question is: for a fixed simulation at a fixed node, I obtain no fracture if I evaluate the FLDCRT (the value is minor than 1), but if I determine the strain path of the same node and I superimpose it on the FLD I have the intersection between the two curves, so I determine fracture at the same node.
So, how can the same simulation give different results only by changing the output variable?
I really hope you can give me a big help since I've tried to find something around the web, but I haven't find anything interesting.
Thanks to all

Antonio

P.S. I hope I've been clear in explaining my problem; sorry for my english! Thanks again.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor