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Formula for guided bend test Jig-diameter API %LC

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DiplingAndre

Petroleum
Nov 19, 2008
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DE
Hello,
I've some problems withe the calculation Fig. 4 in API 5LC
The Formula is A = (1,15(D-2t)/(e-D/t-2e-1))-t
D is for example 16" or 406,4 mm
t = 0,204" or 5,2 mm
e = 0,1025" or 102,5 mm

I think that the formula is not correct coz i found in an old version (1991) A = (1,15(D-2t)/(e*D/t-2e-1))-t

But when I try to calculate i don't get realistic results.
What am i doing wrong?
 
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I see problems with that equation.

One, the variable e is the strain, and should be the same in either USC or metric units (it is a dimensionless variable). In your example, you are saying 0.1025" or 102.5mm, this should be 0.1025 in/in or 102.5 mm/m. If they are going to express the strain in mm/m, then the equation will have to change to accountt for this.

Second, looking at the denominator using the USC uints, (e-D/t-2e-1), D/t ratios are going to be very much larger than the strain values so this term will always be a negative value, which would produce a negative value of A.

You might want to ask your question to API. You can find information for this at
You will want specific in your question by stating you think you have found an error in specification 5LC, then stating what you have posted here.

rp
 
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