skeletron
Structural
- Jan 30, 2019
- 875
During some recent waiting room downtime I decided to decipher the SEAOC Volume 2 guidebook (IBC 2015) and look at how they set up the FTAO calculation. I am familiar with the APA's Diekmann method calculator tool and wanted to have a side by side comparison.
A couple of short questions:
1. The SEAOC example doesn't care about the A.R. above the opening. However, when looking at Malone's Ex.10.4, he checks that aspect ratio and disregards the portion above the opening.
Does the Thompson method disregard the A.R. check because it attributes the wall up to inflection point to the pier?
2. Why is the Thompson method hold down force 200 lbs, but under the same conditions the Diekmann wants to attribute 1000lbs?
3. If there are unequal depth openings, is the Cantilever beam analogy more applicable? Thompson and Diekmann methods seem to need the consistent opening depth assumption.
For reference, the example wall from SEAOC is:
L1, L2, L3, L4 = wall piers = [8, 12.75, 11.5, 11.5] ft
O1, O2, O3 = openings = [9, 4, 4] ft with consistent depth of 4ft, 2.54ft above grade
F = 7612 lbs applied to the wall line
H = 8.21 ft
A couple of short questions:
1. The SEAOC example doesn't care about the A.R. above the opening. However, when looking at Malone's Ex.10.4, he checks that aspect ratio and disregards the portion above the opening.
Does the Thompson method disregard the A.R. check because it attributes the wall up to inflection point to the pier?
2. Why is the Thompson method hold down force 200 lbs, but under the same conditions the Diekmann wants to attribute 1000lbs?
3. If there are unequal depth openings, is the Cantilever beam analogy more applicable? Thompson and Diekmann methods seem to need the consistent opening depth assumption.
For reference, the example wall from SEAOC is:
L1, L2, L3, L4 = wall piers = [8, 12.75, 11.5, 11.5] ft
O1, O2, O3 = openings = [9, 4, 4] ft with consistent depth of 4ft, 2.54ft above grade
F = 7612 lbs applied to the wall line
H = 8.21 ft