mikew79
Electrical
- Nov 4, 2012
- 1
Forgive me for the probable ease of this question, but I am an electrical engineer who rarely is involved in this sort of thing, and its a long while since I did this.
Am I still correct in thinking that the maximum output torque of any single stage gearbox particularly planetary, (assuming 100% efficiency) is the input torque applied to the inverse gearbox ratio. Thus given a motor running at 6000RPM able to deliver a torque of 1NM to a load if put through a 10:1 gear box, I get a Running Speed of 6000/10=600RPM and a torque of 1*10=10NM.
Am I correct in assuming that the nominal torque quoted is just the realistic maximum output torque, if the input torque was sufficent. thus if a Nominal torque of 17NM is quoton a 10:1 gearbox you would only achieve 17NM if you applied 1.7 at the Input, so applying the above 1NM would still only give 10NM.
Thanks
Am I still correct in thinking that the maximum output torque of any single stage gearbox particularly planetary, (assuming 100% efficiency) is the input torque applied to the inverse gearbox ratio. Thus given a motor running at 6000RPM able to deliver a torque of 1NM to a load if put through a 10:1 gear box, I get a Running Speed of 6000/10=600RPM and a torque of 1*10=10NM.
Am I correct in assuming that the nominal torque quoted is just the realistic maximum output torque, if the input torque was sufficent. thus if a Nominal torque of 17NM is quoton a 10:1 gearbox you would only achieve 17NM if you applied 1.7 at the Input, so applying the above 1NM would still only give 10NM.
Thanks