howitz
Electrical
- Nov 19, 2006
- 2
When using a purely resistive loadbank how do you calculate the load current. This is to load check lets say a 100KVA generator at 0.8 powerfactor. this is how i thought it was done
kva = kw/pf therefore if the powerfactor was at unity then 100kva = 100kw therfore the generator would be loaded at 100kw
however i have recently started a new job and the techies say to calculated the load use this formula
100kva * 0.8 = KW then times the answer by 1.39
100kva * 0.8 = 80kw
80kw *1.39 = 111.2 kw
the generator should be loaded at 111.2kw resistive load.
I don't see the relationship of this calculation on any generator i have come across or am i missing something.
I think the answer they gave me was due to the diesel engine fitted to the alternator.
Any help would be appriciated
kva = kw/pf therefore if the powerfactor was at unity then 100kva = 100kw therfore the generator would be loaded at 100kw
however i have recently started a new job and the techies say to calculated the load use this formula
100kva * 0.8 = KW then times the answer by 1.39
100kva * 0.8 = 80kw
80kw *1.39 = 111.2 kw
the generator should be loaded at 111.2kw resistive load.
I don't see the relationship of this calculation on any generator i have come across or am i missing something.
I think the answer they gave me was due to the diesel engine fitted to the alternator.
Any help would be appriciated