h/t for a pole

[greencircle]

Guys,
I need some help with understanding and using h/t ratio for calulating stresses.
On another thread I had learned that h/t for pole refers to diameter to wall thickness. I tried to understand the following pole drawing calculation.

Pole drawing :

There are 2 segments of pole :

Dia 8 x 0.25" wall x 4ft---------------shouldn't h/t be 8/0.25 = 32
Dia 5 x 0.25"wall x 14ft---------------shouldn't h/t be 5/0.25 = 20

One of the PE calcs on file shows this differently

What am I missing something?

Thanks,
GC

 

[SAIL3]

I usually assume that the length of wall that is effective in resisting shear is 2/3 of the dia on each side....
so...(8x2/3x2)/0.25 = 42.67
(5x2/3x2)/0.25 = 26.67 ??...does not match the output shown...
I have not checked this with the latest and greatest AISC code...

 

[SAIL3]

sorry, on second thought, my post above is garbage....it has in it a method to calculate the effective shear area of a pipe, but has no relation to the h/t question the OP posed....so scrap it...

 

[BUGGAR]

Allowable stresses in rounds are usually expressed relative to d/t for local stresses and kl/r for global stresses.