Hair Pin Design 1

[mn321]

I was wondering isf anyone knew how to determine the hairpin required length to be embedded in the slab.
I have 15 kips. If I use 0.9 x .750(#6 bar) x 60 ksi = 37.8 kips. If I wish to determine how long I need the hairpin to penetrate into the slab.

 

[six06]

Is the same concept as transfer length. Just give enough length that the load can be transfered to the bar. There are many ways to do it and i think ACI gives you a formula too.

 

[mn321]

Thaks for the insight. I found the formula from ACI-318 :

Ld = 3*db*fy*B*g
---------------
50*(fc)^0.5