LMW.dk
Civil/Environmental
- Nov 3, 2016
- 29
Can someone explain to me why the hell did he multiply by 4,8m? I mean if it was me and i wanted to find out the the distributed load on the continuous slab then i would have multiplied 12,25 kN/m^2 with 1m = 12,25 kN/m
I'm i wrong or is the book wrong? Thanks in advance.
I'm i wrong or is the book wrong? Thanks in advance.