Help needed for ME Intern: Calculating max lifting force of Cylinder

[garmancm]

On one of my first internships and was assigned a problem I'm pretty intimidated by. I'm not looking for someone to give me the answer outright, but just tell me which specs are pertinent, what info is needed, calculations to use, etc. And then maybe help me as I work through things.

We're using a Tolomatic electric rod style cylinder. Part no. ERD20-BNM20-SM431.8-RP2-YM020019-ARI-FFG-IP67 It has an Animatics motor Part no. SM34165MT-BRK-IP-DN

Here's some of the cylinder specs:

Am I missing any details? Can somebody please help me get started?

 

[IRstuff]

?? The datasheet tells you what the lift force is, so what is your question?

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[garmancm]

So, the cylinder can handle 2224N but can my motor?

 

[kjoiner]

Hello,

I recommend working backwards from the required force and speed to get your torque and power requirements. Visit a site like Thompson or Nook to follow their lead screw calculations for determining required torque. Here are a couple of observations:

1. That's a pretty steep lead (20mm/turn)
2. Is it a ball or lead screw? Is gravity or back driving an issue? If so, you need some method to keep the load in place because the steep lead will result in back driving
3. Your motor generates 3.94 N-m of torque. Run through the calculation to see what maximum linear force it can generate.
4. The motor max rpm is 4900. If you have a high RPM, you may be able to use a screw with a shorter lead but you need to look at the output curve of the motor to decide.

Kyle

 

[grunt58]

Tolomatic's application engineers should be able to help you size your motor. FYI you can get linear actuators with integrated motors. Perhaps not relevant per your post but FYI maybe you can cross-reference.

 

[IRstuff]

Apparently, this is supposed to be a learning exercise for you.

> Does the NEMA frame size 34 even fit your actuator?
> You need to calculate the required torque from the motor to drive the actuator lead screw for the rated load -- your chosen motor has a continuous torque of 1.42 N-m; is that sufficient?

TTFN (ta ta for now)
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[TheTick]

In ideal state, Power = force × speed. The load and speed will tell you the ideal power required. You will need a motor bigger than that.

 

[LittleInch]

Well you're missing from this post as far as I can see:

Speed of your cylinder
Actual load on your cylinder for the required movement
torque required on the intput into the actuator (start and running torque)
What is between your motor ( ~ 3-4,000 rpm) and your cylinder. This could have a LOT of losses.
What you're actually trying to do with this movement? - Just moving something or trying to accurately position something?


You clearly can't attach your puny little high RPM motor directly to this actuator??

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