charz
Electrical
- Jan 11, 2011
- 95
If one of the CT is fully saturated for an external fault condition, there would be difference in the currents from the two CT's and if the difference is more than the Pickup, the differential relay trips, as in the following picture,
I read in a literature that, "The knee point voltage (Vk) for class PX CT's used in high impedance scheme is calculated for the worst condition that one of the CT's is fully saturated and the other CT has to develop enough voltage to drive current through the other CT circuit to ensure stability during external fault"
Why the other CT has to develop enough voltage to drive the current through the other CT?
I read in a literature that, "The knee point voltage (Vk) for class PX CT's used in high impedance scheme is calculated for the worst condition that one of the CT's is fully saturated and the other CT has to develop enough voltage to drive current through the other CT circuit to ensure stability during external fault"
Why the other CT has to develop enough voltage to drive the current through the other CT?