Khuzaim Khan
Student
- Dec 24, 2020
- 1
Hello everyone,
I need a motor for my project, but I´m not quite sure if my calculations are correct.
I need a motor to move a 500 kg horizontally (linear motion), where the friction constant is 0.8. The speed should be around 0.3 m/s
To calculate the force required to move the object:
F = m * g *u , F = force, m = mass of object, g = gravity constant, u = friction.
F = 500 kg * 9,82m/s2 * 0.8
F = 3924 N to overcome the frictional forces.
Calculating the motors torque:
T = F * d, where T = torque, F = force, d = radius of wheel
T = 3924 N * 0.101 m
T = 396.324 Nm
Are my calculations alright? Since the torque calculated is the torque that will be needed to overcome friction i will obviously need a little higher torque to account for acceleration.
Will selecting a motor of 420 Nm be alright? with 4 motors I would need 105 Nm motor for each wheel.
Do i need to use a gearbox motor for this purpose? Kindly correct me if I did any mistakes in the previous steps, and how to approach this forward as well. TIA
Kind Regards,
Khuzaim Khan
I need a motor for my project, but I´m not quite sure if my calculations are correct.
I need a motor to move a 500 kg horizontally (linear motion), where the friction constant is 0.8. The speed should be around 0.3 m/s
To calculate the force required to move the object:
F = m * g *u , F = force, m = mass of object, g = gravity constant, u = friction.
F = 500 kg * 9,82m/s2 * 0.8
F = 3924 N to overcome the frictional forces.
Calculating the motors torque:
T = F * d, where T = torque, F = force, d = radius of wheel
T = 3924 N * 0.101 m
T = 396.324 Nm
Are my calculations alright? Since the torque calculated is the torque that will be needed to overcome friction i will obviously need a little higher torque to account for acceleration.
Will selecting a motor of 420 Nm be alright? with 4 motors I would need 105 Nm motor for each wheel.
Do i need to use a gearbox motor for this purpose? Kindly correct me if I did any mistakes in the previous steps, and how to approach this forward as well. TIA
Kind Regards,
Khuzaim Khan