How to calculate the center of gravity of a steel pipe with a weight to the side?

[StathPol12]

Hi guys,

I have a steel pipe with the dimensions shown below:

Length of the pipe = 6.4 metres.
External diameter = 2.48 metres.
Internal diameter = 2.46 metres.
Self-weight of the steel pipe = 6766.85 kg (uniform steel pipe).

A steel door of 120 kg is bolted to the right side of the steel pipe, in the middle. Can you please help me with calculating the centre of gravity?

 

[Luceid]

This is the same as finding the area centroid of any shape, and shouldn't be too difficult to calculate. Just replace area (A) with the weights, and define the corresponding distance from an origin you select, in the following equations (Although you only need to calculate one of them, since the center of gravity is going to be at the center of the pipe in two directions).

This seems like a student question, which would probably be better to post in the student forum. Would prefer not to do your work for you, but I'm happy to check the result you get .

 

[StathPol12]

Thanks for the reply. If it was a 2D beam, I can do it. But here, we have a 3D steel pipe with a door weight of 120 kg to the side in the middle and it confuses me. Shall I treat it like a 2D and solve it with reference A the start point of the pipe?

And I need to get it ready by tmr ..I am just stuck

 

[Luceid]

Responded in student forum, delete this post when you get a chance

 

[robyengIT]

1 - since the structure is symmetrical all along the length of the pipe, the CG is on the middle of said length
2 - in the other direction you can make a section as below

 

[rb1957]

"P" is the total weight ... pipe and door.

"Hoffen wir mal, dass alles gut geht !"
General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus.

 

[robyengIT]

"P" : weight of pipe only (without the void of the door; and, of course, it is not exactely on centerline)