HOW TO IDENTIFY A CONICAL/CYLINDRICAL FACE

[Alex_59]

Hello everyone,


I'm a beginner in abaqus Scripting and I'm trying to automate a modelisation but I don't know how to identify if a face is conical or cylindrical, is there an instruction for that?

When I use this instruction in my code, my program stops working when it finds a not conical/cylindrical face:

for x in range(len(f)):
myAxis = p.DatumAxisByCylFace(face=f[x])


If you have some answers, thank you!!

 

[Erik Panos Kostson]

Not sure, but perhaps if you have calculated the curvature of a face (I assume it will give a zero 0, or close to a zero if flat), and then have an if statement that the curvature needs to be greater than zero (or greater than some small numerical tolerance) in order to do the DatumAxis. (There should be a command for calculating the curvature)