how to project a point onto a curve

[boffin5]

This sounds like it should be easy, but it is defying me. I have a 3D curve, and a point in space that is not on the curve. The point is positioned such that a normal projection is possible, but I haven't been able to create that new point. I've tried everything, but am at my wits end. Help!

 

[Guest0527211403]

If you have BMX installed, you can do this using an analysis feature.

Create a distance measurement from the point to the curve. This will measure the shortest distance from the curve to the point Then hit the "Add Feature" button. Then, redefine the analysis feature. Press Compute once again, and then in the tree in the dialog box choose "Result Datums". Choose yes for the second datum point and name it accordingly. This new point is your projected point.

The angle between the curve and the axis created by the two points should be 90 degrees.

Good luck!

 

[3dlogix]

Why not create a datum curve that starts at the point, and extend it past the original curve. Once it intersects the first curve, create a datum point using crv x crv.

Steve

http://www.sprdesign.com

http://www.3dlogix.com

 

[boffin5]

Justkeepgivener,

It worked! I managed to use a laborious workaround before your post, but next time I'll be ready! Thanks!

 

[jeff4136]

To solve for a line from point, normal to curve (without BMX, is shortest distance always a normal vector?) I've used a VSS. ...

http://www.mcadcentral.com/proe/forum/forum_posts.asp?TID=26390

(kinda long winded discussion)

VSS example in WF2

http://www.mcadcentral.com/proe/forum/uploads/jeff4136/2005-02-09_123750_vss_solution_WF2.zip

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I haven't ever tried it, but if shortest distance is always along a normal vector the trajpar_of_pnt function might solve, too.

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