crinners
Mechanical
- Mar 18, 2014
- 1
Hi I read post thread391-248736 and was interested by the post from 25362
would anyone happen to have a diagram showing this more clearly? I was unsure as to what p would be as a distance, is this circumferential? and if so at which point of the fin?
Thanks
25632 said:Hydraulic equivalent diameter of finned tubes (dHe)
df = external diameter of fin
do = external diameter of bare pipe
p = face-to-face distance between adjacent fins
t = fin thickness
dHe = [(df2- do2)/2p + dft/p + do(1 - t/p)] ÷ [1 + (df - do)/p]
would anyone happen to have a diagram showing this more clearly? I was unsure as to what p would be as a distance, is this circumferential? and if so at which point of the fin?
Thanks