Ice is less dense than water. Water weights 62.428 lbs/cu.ft.. In determining the radial ice on a conductor per foot, should I use 92% of the weight of water or is there an more acceptable number?
WI = Ice loading, in newtons per meter
d1 = Outside diameter of conductor with ice, in centimeters d2 = Outside diameter of conductor without ice, in centimeters
WI = 0.311(d1^2-d2^2)
WI = Ice loading, in pounds per foot
d1 = Outside diameter of conductor with ice, in inches
d2 = Outside diameter of conductor without ice, in inches
Thank you for the reference RUS 1724e300. I had seen that factor .311 and tried to determine how it was calculated. Part is the conversation of unit to feet and part was the weight of ice. The weight of ice was the unknown. Not anymore. Thank you again.