For a ground fault or single-phase-to-ground fault, the symmetrical component solution is a series connection of Z1, Z2 and Z0. The resulting current, I1, will be obtained from V/(Z1+Z2+Z0). For the actual fault current, If, you need to multiply I1 by 3.
Symmetrical Components for Power System Engineering - by Blackburn - this was meant to be a companion to his relaying book
Circuit Analyses of A-C Systems vol. 1 and 2 by Edith Clarke - both of these volumes are very well written. She does a very good job at explaining and giving insight into her analyses. This is out of print and it is hard to find original copies but it is out of copyright and you can get a pdf through most universities if you have access or can purchase a copy of from India as a print on demand hardcover for $15-20 a vol. (
I think what do you need to know-or calculate-are the positive, negative and zero sequence impedances of different elements of a schematic diagram in order to calculate the phase-to-ground fault short-circuit current.
If you intend to follow IEC way-IEC 60909-0 for instance-you have IEC 60909-2 SECTION 2: DATA FOR ELECTRICAL EQUIPMENT. You could find here data on typical synchronous, induction machines, transformers, overhead line and cables.
