Is this force ditribustion in planetry gear train is correct

[thought2007]

Hi,
I am trying to design epicyclic gear train.
in which

Input :sun gear
output:carrier through 3planetry gears
fixed :Ring gear

i analysed as follows

Input force (from sun)=Fs
Force at single planet gear=Fp=Fs/3
Force at ring gear=fr=Fs
Force at Carrier=3*Fp

its bit confusing for me to anlyse force distribution in gear train,is above analysation is correct?.

any advice is appreciable

Thanks in before

John

 

[MikeHalloran]

I think equilibrium requires that

Force at Carrier=2*Fp for each planet gear

... but planetaries make my head hurt, so maybe you need to re-read the chapter.





Mike Halloran
Pembroke Pines, FL, USA

 

[israelkk]

thought2007

Don't you mean torque (not force)?

 

[dimjim]

Force is correct. Not Torque.
Torque is force times a radius.

 

[gearguru]

The forces have to be calculated from the input torque and the sizes (no. of teeth) of all parts.
If only output torque is necessary, then it can be calculated as: (input torque)*1/(speed ratio)

 

[israelkk]

dimjim

The sun gear input is torque which creates a force on the sun and planets teeth. Therefore, when thought2007 statement "Input force (from sun)=Fs" it is not accurate.