SD12
Mechanical
- Apr 8, 2020
- 12
Hello.
I try to understand the following equation: Kv = Q / sqrt(delta p), whre "Kv" is in m^3/s, "Q" is in m^3/s and "delta p" is in MPa (or bar).
If we divide flow (m^3/s) by the square root of pressure difference (MPa), how do we get the value of Kv to be in m^3/s?
Please, give me an example if possible.
Best regards,
Sergey
I try to understand the following equation: Kv = Q / sqrt(delta p), whre "Kv" is in m^3/s, "Q" is in m^3/s and "delta p" is in MPa (or bar).
If we divide flow (m^3/s) by the square root of pressure difference (MPa), how do we get the value of Kv to be in m^3/s?
Please, give me an example if possible.
Best regards,
Sergey