I've been asked to pursue the SS6.2 Storm Water Quality Credit for one of my projects, a 3 acre parking lot. The requirements state that the BMP(s) need to be "designed to treat stormwater runoff from 90% of the average annual rainfall." I also understand that treating 90% of the average annual rainfall is equivalent to treating 0.5 inches of rainfall in Arid Watersheds, such as where my project is.
The treatment device selected (5K Baysaver) has the ability to treat 11.1 cfs. My question is:
How do I compare 0.5 inches of rain with the 11.1 cfs? Doesn't it depend on whether the 0.5 inches comes down really fast, or takes its time? For example, the 1-year 2-hour storm would drop about 0.5 inches near my project according to NOAA depth-duration-frequency chart. However, the 100-year 5-minute storm would also drop about 0.5 inches. Therefore, the 1-year storm would be dropping an average intensity of 0.5/2 = 0.25 in/hr, while the 100 year storm would drop an average intensity of 0.5/(5/60) = 6 in/hr.
Therefore, 0.5 inches for a 1-year storm would produce a rate of Q=CIA=0.9*0.25*3=0.68 cfs. And 0.5 inches for a 100 year storm would produce a rate of Q=CIA=0.9*6*3=16.2 cfs.
So, for a 1-year storm, I would meet the 90% treatment requirement. But, for a 100-year storm I would not.
How can I reconcile this? Am I going about this calculation the correct way?
RYan
The treatment device selected (5K Baysaver) has the ability to treat 11.1 cfs. My question is:
How do I compare 0.5 inches of rain with the 11.1 cfs? Doesn't it depend on whether the 0.5 inches comes down really fast, or takes its time? For example, the 1-year 2-hour storm would drop about 0.5 inches near my project according to NOAA depth-duration-frequency chart. However, the 100-year 5-minute storm would also drop about 0.5 inches. Therefore, the 1-year storm would be dropping an average intensity of 0.5/2 = 0.25 in/hr, while the 100 year storm would drop an average intensity of 0.5/(5/60) = 6 in/hr.
Therefore, 0.5 inches for a 1-year storm would produce a rate of Q=CIA=0.9*0.25*3=0.68 cfs. And 0.5 inches for a 100 year storm would produce a rate of Q=CIA=0.9*6*3=16.2 cfs.
So, for a 1-year storm, I would meet the 90% treatment requirement. But, for a 100-year storm I would not.
How can I reconcile this? Am I going about this calculation the correct way?
RYan