sanan-monteed
Computer
- Dec 31, 2024
- 1
b=350mm
d = 450mm
number of bars = 5
dia of bars = 12mm
Fck = 25
Fy = 415
Ast = 565.56
l(length) = 4.5m
Xu = (0.87 x Fy x Ast)/(0.36 x Fck x b)
Xu = 64.82 mm
Xumax = 0.48(d)
Xumax = 216mm
Xu < Xumax = Under reinforced
Mu = 0.87 x Fy x Ast (d - (0.42 x Xu))
Mu = 86.329 KN/m
BM = Wu(l x l)/8
Wu = Mu(8)/(lxl)
Wu = 34.105 KN/m
W = Wu/1.5
Safe Load = 22.74 KN/m
d = 450mm
number of bars = 5
dia of bars = 12mm
Fck = 25
Fy = 415
Ast = 565.56
l(length) = 4.5m
Xu = (0.87 x Fy x Ast)/(0.36 x Fck x b)
Xu = 64.82 mm
Xumax = 0.48(d)
Xumax = 216mm
Xu < Xumax = Under reinforced
Mu = 0.87 x Fy x Ast (d - (0.42 x Xu))
Mu = 86.329 KN/m
BM = Wu(l x l)/8
Wu = Mu(8)/(lxl)
Wu = 34.105 KN/m
W = Wu/1.5
Safe Load = 22.74 KN/m