ypwtb
Mechanical
- May 26, 2007
- 7
Hello,
Why is Trane using 150% of FLA for the electrical requirement of a convenience outlet on a rooftop unit in page 36 of this document?
Isn't this supposed to be the contribution of the outlet to the total MCA (minimum circuit amps) for the unit?
They list the imposed load of a 15-amp, 115 volt convenience outlet on a 208/60/3 unit as 7.21 amps.
Shouldn't it be 1.25 * (115/208) * (15 amps / sqrt(3)) = 5.985 ... say 6 amps?
It is 6 amps on page 13 of Carrier's document here:
Comparing the MCA values in the 3rd and 4th lines of Table 1A for a model 48HJ004 with 208/3/60 power:
[ul][li]The 3rd line says 27.2 MCA with _no_ convenience outlet.[/li]
[li]The 4th line says 33.7 MCA _with_ a convenience outlet.[/li][/ul]
The difference is 6 amps = 125% of FLA.
Which seems to contrast with:
7.21 / ((115/208) * (15 / sqrt(3))) = 1.506
So why is Trane saying 150% of FLA for the electrical requirement of the convenience outlet?
I am a mechanical engineer who is trying to figure out how to get the right numbers to the electrical engineers on my projects. I thought that I understood the MCA calculation until I found Trane's number at what seems to be 150% of FLA.
Please help me to understand why Trane's number is higher than I expected it to be for the convenience outlet.
Thanks,
Yittri
Why is Trane using 150% of FLA for the electrical requirement of a convenience outlet on a rooftop unit in page 36 of this document?
Isn't this supposed to be the contribution of the outlet to the total MCA (minimum circuit amps) for the unit?
They list the imposed load of a 15-amp, 115 volt convenience outlet on a 208/60/3 unit as 7.21 amps.
Shouldn't it be 1.25 * (115/208) * (15 amps / sqrt(3)) = 5.985 ... say 6 amps?
It is 6 amps on page 13 of Carrier's document here:
Comparing the MCA values in the 3rd and 4th lines of Table 1A for a model 48HJ004 with 208/3/60 power:
[ul][li]The 3rd line says 27.2 MCA with _no_ convenience outlet.[/li]
[li]The 4th line says 33.7 MCA _with_ a convenience outlet.[/li][/ul]
The difference is 6 amps = 125% of FLA.
Which seems to contrast with:
7.21 / ((115/208) * (15 / sqrt(3))) = 1.506
So why is Trane saying 150% of FLA for the electrical requirement of the convenience outlet?
I am a mechanical engineer who is trying to figure out how to get the right numbers to the electrical engineers on my projects. I thought that I understood the MCA calculation until I found Trane's number at what seems to be 150% of FLA.
Please help me to understand why Trane's number is higher than I expected it to be for the convenience outlet.
Thanks,
Yittri