sshep
Chemical
- Feb 3, 2003
- 761
My Friends,
In several previous posts (example: thread124-181137) there is a question about how cold you can get blowing a hydrocabon system dry with N2. I haven't always felt we were that useful, but now that I was asked to specify some rail car MDMT for pentene service, the question was asked of me to calculate exactly that question: How cold can it get when purging with N2. Using Aspen plus I could get an answer by sensitivity analysis on N2 and Pentene, finding the minimum point (when the last liquid disappears). The temperatures were much colder than my peers realized, reaching (theoretically) below -30C. I knew the temperatures would be well below the boiling point, but didn't have reasoning that could be well communicated. Now I do.
Before I submit my conclusions I would like you to check my reasoning: The N2 and liquid hydrocarbon mix, some hydrocarbon evaporates and carries away heat from the remaining liquid. The minimum temperature can be calculated by energy balance. We could even calculate dT/dt, but we only care about the final temperature (dT/dt=0).
The enthalpy of incoming N2 is balanced by the heat being removed by evaporation:
Equation #1: N2flow*Cp*(Tsupply-T)=HCflow*HVap, where
T is the mixture temperature
N2flow is the nitrogen flow
Tsupply is the N2 supply temperature
HCflow is the hydrocabon flow leaving (evaporated)
HVap is the molar heat of vaporization
Cp is the molar N2 heat capacity
The HCflow depends on the vapor pressure, system pressure, and flow of N2
Equation #2: HCflow=N2flow * PL /(P-PL), where
PL is the vapor pressure which is a function of T from Antoine's equation
By reducing this down, the N2 flow drops out:
Cp*(Tsupply-T)=PL*HVap/(P-PL)
Since PL=f(T), this is most easily solved using the solver function in Excel.
The parameters that make the difference for a particular system are the N2 supply temperature, and the total system pressure (typically atmospheric worst case).
Does this seem right to you guys? Any comment is appreciated.
best wishes always,
sshep
In several previous posts (example: thread124-181137) there is a question about how cold you can get blowing a hydrocabon system dry with N2. I haven't always felt we were that useful, but now that I was asked to specify some rail car MDMT for pentene service, the question was asked of me to calculate exactly that question: How cold can it get when purging with N2. Using Aspen plus I could get an answer by sensitivity analysis on N2 and Pentene, finding the minimum point (when the last liquid disappears). The temperatures were much colder than my peers realized, reaching (theoretically) below -30C. I knew the temperatures would be well below the boiling point, but didn't have reasoning that could be well communicated. Now I do.
Before I submit my conclusions I would like you to check my reasoning: The N2 and liquid hydrocarbon mix, some hydrocarbon evaporates and carries away heat from the remaining liquid. The minimum temperature can be calculated by energy balance. We could even calculate dT/dt, but we only care about the final temperature (dT/dt=0).
The enthalpy of incoming N2 is balanced by the heat being removed by evaporation:
Equation #1: N2flow*Cp*(Tsupply-T)=HCflow*HVap, where
T is the mixture temperature
N2flow is the nitrogen flow
Tsupply is the N2 supply temperature
HCflow is the hydrocabon flow leaving (evaporated)
HVap is the molar heat of vaporization
Cp is the molar N2 heat capacity
The HCflow depends on the vapor pressure, system pressure, and flow of N2
Equation #2: HCflow=N2flow * PL /(P-PL), where
PL is the vapor pressure which is a function of T from Antoine's equation
By reducing this down, the N2 flow drops out:
Cp*(Tsupply-T)=PL*HVap/(P-PL)
Since PL=f(T), this is most easily solved using the solver function in Excel.
The parameters that make the difference for a particular system are the N2 supply temperature, and the total system pressure (typically atmospheric worst case).
Does this seem right to you guys? Any comment is appreciated.
best wishes always,
sshep