Motor / Pump cooling.

[tjmurf]

Motor and pump cooling application:

Would it be safe to assume that the difference between brake hp and water hp equals the power loss through the application?
This loss will equal the heat that the pump and motor will create and must be removed / cooled.

Example:
100% duty cycle.
Water hp to deliver X gallons @ X head = 75 hp.
Brake hp to deliver the same @ same = 100 hp
Difference equals 25 hp of heat to dissipate.

Is it this simple? What am I missing?

TM

 

[CJCPE]

Water Hp / pump efficiency = brake Hp. Water Hp - brake Hp = heat transferred to water and ambient from the pump.

Brake Hp X 0.746 = kW mechanical power delivered at motor shaft. KW at motor shaft / motor efficiency = electrical kW input at motor terminals. Motor shaft kW - terminal kW = heat transferred to ambient from the motor.

 

[aolalde]

Yes 25 HP is the heat loss in the pump and pipe up to the discharge. Note that the motor loss is not included.