Motor rpm 6

[Kumar G]

Dear Members,
Request some to clear a clarification that, an electric motor having 1400 rpm , 1.1 kw 415 V , 3 phase, is assembled with a gear box delivering the output rpm of 391 and the torque is 66 nm, we wants to increase the output rpm of the gear box as double like 782 as unaltered the torque of the gear box and the input power of the motor as it is. Can we replace the motor by an another one having 2800 rpm, or is there any other solution to attain as mentioned above.

Thanks & Warm Regard,

Kumar.

 

[handleman]

No, it is not possible.

Your original statement is not possible either.

A 1.1kW motor cannot deliver 66N*m of torque at 391 rpm, no matter what gearbox you have. 66N*m at 391rev/min = 2.7kW.

 

[rb1957]

"we wants to increase the output rpm of the gear box as double like 782 as unaltered the torque of the gear box and the input power of the motor as it is." you want to double the torque at the same rpm (ie double the output work) with the same input work ... surely you can see this doesn't make sense.

handleman points out an inconsistency with your problem statement ... maybe you mean 1.1kw per phase ?

if you double the power into the gear box, you might get double the power out, for a time, but you'll probably break it.

another day in paradise, or is paradise one day closer ?

 

[LittleInch]

"or is there any other solution to attain as mentioned above."


Yes, Buy a motor rated at 6kW and also a new gearbox..

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.

 

[robyengIT]

P = (T * 2 * 3.14 * n)/60 : power = (torque * 2 * 3.14 * RPM)/60 . If the power is a statement of the motor (that is constant), if you double the RPM then the torque has to be divided by 2 !!!