Multiphase Pump

[CryoDouche]

Hey guys! Got a couple of questions regarding the BHP of a Pump.

We're trying to pump 700 BPD of heavy oil with a GVF of 95%. We want to calculate the power required for the pump. I know BHP=Q(GPM)*TDH(FT)*sp.gr/(3960*Eff(%)); my question is, do I use only the 700 bpd or the BPDe (BPD + GAS) of the mixture? Or do I just change the sp.gr. of the liquid to that of the mixture (gas + liquid).

Hope you can help me with this issue.

Thank you in advance!

 

[georgeverghese]

Just as in oil flooded screw compressors in gas service, you'll need to ask the 2phase pump vendor for this application with 95% gas void fraction.

 

[DubMac]

Yes, of course ask the vendor, but......

Your driver must be prepared for 100% continuous slugs of full blown oil. Right?

 

[CryoDouche]

Is it correct to assume 700 BPD without gas, to calculate the maximum BHP required for the pump?.

 

[LittleInch]

If you can get a much lower GVF, then that becomes your design value. Wholly depends on how well the incoming flow is conditioned or monitored to maintain a fixed or minimum GVF.

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.

 

[CryoDouche]

GVF is not stable. That's why we want to find out, how to calculate the power required for the MPP.

 

[LittleInch]

That's my point - eve if you only get 50% but for 10 seconds, then that is your worst case.

MPP?

If you want to cover all bases, then yes 100% liquid at 700 bpd should be pretty bullet proof, but apart from cost and start current, there's not much else wrong about a motor only normally working at 20% of its power output.

either that or accept a trip every now and then.

What happens on start/stop is probably the most crucial. If the liquid can gather in one place or enter the pump in a much larger amount than during steady state conditions, then you should go for 100% of liquid.

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.