RudyRuude
Mechanical
- Feb 24, 2014
- 6
Hello,
Firstly, I have been struggling with the units associated with natural gas composition and converting said units to other units. A common roadblock that I experience is a customer will send me a natural gas composition with "ppm" listed for certain contaminants such as H2S, CO2, N2 and H2O. I know I can, and probably should, always ask them to clarify what their units are, but the use of "ppm" without specifying volume, mass or molar seems to be all over the internet so I'm wondering if I'm missing something here? Is there a rule of thumb for when "ppm" is used? Can I assume that ppm is given as a molar basis when it concerns gas composition? From my understanding, ppm_molar, ppm_mass and ppm_volume will have completely different values (provided gas compressibility is taken into account). I should mention that I'm a recent Mechanical Engineering grad and Chemistry was never my strong subject.
Secondly, given a complete (or nearly complete) gas analysis on a molar basis (mole fractions), part of my job is to verify the gas suitability for use in our Thermoelectric Generators. For example, I was given a spec with 0.79%mol H2O. The customer converted this to mg/Sm3 where the standard conditons are taken at 1 atm and 15C. The value they gave was 17160 mg/Sm3 (for 0.79%mol H2O), but when I do the calculation myself, I end up with 6022.6 mg/Sm3. My calculation is as follows:
1) Calculate mass of H2O per mol of gas mixture using molar mass of H2O: 0.0079 [mol_H2O/mol_mixture] * 18015.28 [mg_H20/mol_H2O] = 142.32 [mg_H2O/mol_mixture]
2) Calculate molar volume at 15C and 1 atm: V = 8.314*288/101325 = 0.023631 [m3/mol_mixture] <---- Ideal gas law
3) Calculate mg/Sm3 of H2O: 142.32 [mg_H2O/mol_mixture] / 0.023631 [m3/mol_mixture] = 6022.6 [mg/Sm3]
Am I doing something wrong/not accounting for something in my calculation? What could be the reason the customer calculated such a high number?
Sorry for the multiple questions in one thread - I maybe should have split them up into separate ones. Thank you in advance for your feedback.
Firstly, I have been struggling with the units associated with natural gas composition and converting said units to other units. A common roadblock that I experience is a customer will send me a natural gas composition with "ppm" listed for certain contaminants such as H2S, CO2, N2 and H2O. I know I can, and probably should, always ask them to clarify what their units are, but the use of "ppm" without specifying volume, mass or molar seems to be all over the internet so I'm wondering if I'm missing something here? Is there a rule of thumb for when "ppm" is used? Can I assume that ppm is given as a molar basis when it concerns gas composition? From my understanding, ppm_molar, ppm_mass and ppm_volume will have completely different values (provided gas compressibility is taken into account). I should mention that I'm a recent Mechanical Engineering grad and Chemistry was never my strong subject.
Secondly, given a complete (or nearly complete) gas analysis on a molar basis (mole fractions), part of my job is to verify the gas suitability for use in our Thermoelectric Generators. For example, I was given a spec with 0.79%mol H2O. The customer converted this to mg/Sm3 where the standard conditons are taken at 1 atm and 15C. The value they gave was 17160 mg/Sm3 (for 0.79%mol H2O), but when I do the calculation myself, I end up with 6022.6 mg/Sm3. My calculation is as follows:
1) Calculate mass of H2O per mol of gas mixture using molar mass of H2O: 0.0079 [mol_H2O/mol_mixture] * 18015.28 [mg_H20/mol_H2O] = 142.32 [mg_H2O/mol_mixture]
2) Calculate molar volume at 15C and 1 atm: V = 8.314*288/101325 = 0.023631 [m3/mol_mixture] <---- Ideal gas law
3) Calculate mg/Sm3 of H2O: 142.32 [mg_H2O/mol_mixture] / 0.023631 [m3/mol_mixture] = 6022.6 [mg/Sm3]
Am I doing something wrong/not accounting for something in my calculation? What could be the reason the customer calculated such a high number?
Sorry for the multiple questions in one thread - I maybe should have split them up into separate ones. Thank you in advance for your feedback.