Non perpendicular bar reinforcement (Wood-Armer?)

[Alvarobg]

Hi everyone,
I am working in a flat slab (50-60 cms), and I have a design with some families reinforcement not perpendicular to bending moment (see attached figure). All of them are situated at the same height approximately.
The ratios of the different families are for example:
-Family 1 (red)= 10 cm[sup]2[/sup]/m
-Family 2 (green)= 5 cm[sup]2[/sup]/m
-Family 3 (blue)= 12 cm[sup]2[/sup]/m
I was wondering how can i quantify the total area of reinforcement provided to withstand the bending moment.
I have read some articles about wood-armer rule, and I think it could be something like this:
Total area (cm[sup]2[/sup]/m)= 10 cm[sup]2[/sup]/m + 5 cm[sup]2[/sup]/m · (cos (30º))[sup]2[/sup] + 12 cm[sup]2[/sup]/m · (cos (60º))[sup]2[/sup]

Thank you.

 

[BAretired]

Looks correct to me:
Total area = 10 + 5 cos[sup]2[/sup](30) + 12 cos[sup]2[/sup](60) = 20.3 cm[sup]2[/sup]/m
except that if the bars are crossing each other, they can't all be at the same height.


BA