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Open Delta

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2000Kvar

Electrical
May 29, 2006
12
How are you able to derive 3 phase power from an open delta configuration. What is the mathematic behind this?
 
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It is similar to taking 208 volts from two 120 volt transfrmers in a 120/208 volt installation.
Vectors will answer this easier than mathematics.
respectfully
 
S = Uab x Ia' - Ubc x Ic'
All values above are phasors (complex numbers).
' is the complex conjugate operator.

Then
P = real(S)
Q = imag(S)

Regards
 
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