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Output Torque of Gearbox 1

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RobynP

Industrial
Jan 18, 2005
1
Being new to the industry, I'm having trouble trying to calculate the output torque of a gearbox with an input torque of 10 Newton meter and a ratio of 10:1. Can anyone give me a tip on how to figure this?
 
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The easiest way to figure it out is based on the energy conservation laws.
Power out + loss = Power in

If we disregard the losses, Pi = Po
P= Torque *rpm

Since ratio 10 to 1 means RPMout = (RPMin)/10

Pi = 10 (N*m) * RPMin
Po = Tout (N*m) * RPMout = Tout*(RPMin) / 10
or
Tout*(RPMin / 10) = 10*RPMin
Tout = (10*RPMin)/(RPMin/10) = 10*10 = 100 (N*m)
 
The gear efficiency (losses) must be taken into account because one maybe fall down even to 50%.
 
Typical efficiencies for precision steel manufactured gearboxes in the range of 10 N*m torque, single stage 10:1 ratio are in the range of 90%.
 
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