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Paralleling ct's of two circuits into one meter 1

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meterman3

Electrical
Dec 28, 2010
3
My question is can I meter two three phase circuits with 200:5 cts. with one form 9S meter? Will these cts be additive.
 
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Yes. If the phase relation is 0 degrees. To add CTs means that they shall be parallelled, not seies connected.

Gunnar Englund
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100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...
 
What Gunnar said, but they add as phasors (vectors). If you are looking for highly accurate metering, this probably will not work very well.

David Castor
 
Actually, adding as phasors means that the kW metering should be quite accurate even if the circuits are at differing power factors.


Bill
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"Why not the best?"
Jimmy Carter
 
I presume when you design/modify a CT circuit that you should do some check regarding CT saturation. If you have CT's A and B feeding the meter, then current in CT B contributes to voltage seen at CT A secondary. Since both CT circuits are similar I presume for simplicity you could assume that each individual CT circuit sees double the impedance of the meter and any shared wiring.

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(2B)+(2B)' ?
 
and of course you add to that the impedance of any other non-shared wiring/devices.

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(2B)+(2B)' ?
 
Saturation is not an issue with properly applied metering class CTs.
I believe that the spec on metering class CTs is to maintain acceptable accuracy at rated burden and 200% current.
Saturation is an issue with protection class CTs. Acceptance testing includes checking saturation voltages to verify acceptable operation at anticipated fault current levels.

Bill
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"Why not the best?"
Jimmy Carter
 
I think ePete is considering CT burden rather than saturation. Burden certainly does need to be considered, although most modern electronic meters have such a low burden that it is unlikely to be a problem, maybe more so with long leads and an electro-mechanical meter.

Metering class CTs are designed to saturate to protect the meter from high secondary currents in the event of a through-fault.


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Yes, accuracy is certainly the relevant issue, not "saturation". My apologies for sloppy terminology.

The more direct calc (instead of doubling impedance) would of course be:
Va = Ia * Za_unshared + (Ia + Ib) * Za_shared

Since Scotty mentioned protecting the meter, it brings to mind a question what kind of thermal limit the meter input has? (and could it be challenged?)



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(2B)+(2B)' ?
 
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