lippy
Mechanical
- Dec 19, 2002
- 18
Hello,
Here is the problem and what I think could be the solution based on the Bernoulli equation, but it seems too simple to be true.
We have say 1000 cfm(@0"sp) being delivered to a ceiling plenum of 10ft x 10 ft. with .50" holes spaced every 4". That means I have 900 .50" holes giving me a "thru" area of approx. 175 (sq. in.). Now if I compute V=Q/A, I get a velocity of 822 ft/min.
I want to know if I can use this velocity plugged into the equation ---delta(P)=(V/4005)*2. Then apply this delta(P) to my blower curve and acuratelly "de"-rate the blower delivery. Oh yea, I did validate the the 4005 number...Oh the memories. Thanks, Joe (lippy).
Here is the problem and what I think could be the solution based on the Bernoulli equation, but it seems too simple to be true.
We have say 1000 cfm(@0"sp) being delivered to a ceiling plenum of 10ft x 10 ft. with .50" holes spaced every 4". That means I have 900 .50" holes giving me a "thru" area of approx. 175 (sq. in.). Now if I compute V=Q/A, I get a velocity of 822 ft/min.
I want to know if I can use this velocity plugged into the equation ---delta(P)=(V/4005)*2. Then apply this delta(P) to my blower curve and acuratelly "de"-rate the blower delivery. Oh yea, I did validate the the 4005 number...Oh the memories. Thanks, Joe (lippy).