Problem with the use of vector elements in Given-Find block

[Pederator]

Hello all,

I have such a problem - I want to use vector elements variables, ie. x[1 instead of x.1 in the Given-Find block, but I can not, because I get "Something is wrong with the solve block used to define this function" error. Anybody know why I can not use vector elements variables? I have also noticed that ie. if I write x[1 = 1 and in the next line x[1 = 2 Mathcad redefines previously defined variable, but there is no green underline and no "This expression redefines a previously defined variable" inscription, as it is when typing x.1 = 1 and then x.1 = 2. I use MC15.

Thanks in advance for help.
Pederator

 

[IRstuff]

It just doesn't. You should define the solve block with a single variable and assign the find to a function, ala,

fcn(x) := find and then pass your vector to x

TTFN
faq731-376

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Of course I can. I can do anything. I can do absolutely anything. I'm an expert!

 

[Pederator]

Can you please attach an example or explain more detailed? I used to assign Find to a column vector, ie. (origin 1)

|x[1|
|x[2|:=Find(x.1,x.2,x.3)
|x[3|

Thanks for help.

 

[IRstuff]

why can't you do X := find(x.1, x.2, x.3) and then access the elements with X[1, X[2, X[3

TTFN
faq731-376

Need help writing a question or understanding a reply? forum1529

Of course I can. I can do anything. I can do absolutely anything. I'm an expert!

 

[Pederator]

Because i ususally find elements that are not started from 1, and also these are various variables, ie. m.4, m.7, m.8, m.9, h.7, h.9 etc. Above was just an example.