RVAmeche
Mechanical
- Jan 20, 2015
- 831
Hi,
I'm a pretty new mechanical engineer a couple years of college. Recently I've started getting involved in PRV sizing and piping calculations at work. I've been trying to educate myself on the requirements from ASME, API, etc.
API 520 states that the Critical Pressure is the lowest pressure possible at the nozzle exit of the relief valve and provides an equation to calculate this (below).
For an example, air k = 1.4, Set Pressure = 180 psig, Fire Scenario Relieving Pressure = 232.5 psia
P(cf) = P(1)*(2/(k+1))^(k/(k-1))
For k = 1.4, P(1) = 232.5 psia, P(cf) comes out to 122.8 psia.
For a given discharge pipe, the maximum allowable dP (lets refer to this dP as P(cf) - P(2) ) is either 10% Set Pressure or 21% Set Pressure depending on the determining the case. If P(cf), which essentially defines the starting pressure of the discharge piping, is 122.8 psia and P(2)is 14.7 psia for atmospheric discharges. How can the discharge piping dP ever fall within the allowable range?
I'm a pretty new mechanical engineer a couple years of college. Recently I've started getting involved in PRV sizing and piping calculations at work. I've been trying to educate myself on the requirements from ASME, API, etc.
API 520 states that the Critical Pressure is the lowest pressure possible at the nozzle exit of the relief valve and provides an equation to calculate this (below).
For an example, air k = 1.4, Set Pressure = 180 psig, Fire Scenario Relieving Pressure = 232.5 psia
P(cf) = P(1)*(2/(k+1))^(k/(k-1))
For k = 1.4, P(1) = 232.5 psia, P(cf) comes out to 122.8 psia.
For a given discharge pipe, the maximum allowable dP (lets refer to this dP as P(cf) - P(2) ) is either 10% Set Pressure or 21% Set Pressure depending on the determining the case. If P(cf), which essentially defines the starting pressure of the discharge piping, is 122.8 psia and P(2)is 14.7 psia for atmospheric discharges. How can the discharge piping dP ever fall within the allowable range?