AO1958
Industrial
- Mar 13, 2009
- 73
Hello,
I don't want to make you an odd question but I am facing to the concept of pump evaporator.
I'd like to understand a little more concerning the way of working of the system.
In detail, I would understand how to determine the enthalpic way to determine the capacity.
I would suppose that the enthalpic difference would be given from
(h out - h in)
where h out = latent/feed rate
my question would be:
obviously
capacity = mass flow * enthalpy difference
the question - hope not odd - is
is the mass flow equal feed rate times the standard mass flow it would have with a DX system ?
Many thanks
I don't want to make you an odd question but I am facing to the concept of pump evaporator.
I'd like to understand a little more concerning the way of working of the system.
In detail, I would understand how to determine the enthalpic way to determine the capacity.
I would suppose that the enthalpic difference would be given from
(h out - h in)
where h out = latent/feed rate
my question would be:
obviously
capacity = mass flow * enthalpy difference
the question - hope not odd - is
is the mass flow equal feed rate times the standard mass flow it would have with a DX system ?
Many thanks